Web4 apr. 2024 · a 3 − b 3 = ( a − b) ( ( a − b) 2 + 2 a b + a b) Now, put values of ( a − b) and ab to the above expression. One may find the exact values of a and b as well by solving the expression a – b = 3 and ab = 10. So, replace, a by b + 3 to the expression ab = 10. So, we get b (b + 3) = 10 b 2 + 3 b − 10 = 0 b 2 + 5 b − 2 b − 10 = 0 Weba-b = 3. a^2+b^2 = 29. Let's Get The Answer In (a-b)^2 Formula/Format (a-b)^2=a^2+b^2-2ab =>3^2 = 29 - 2ab =>9 = 29 - 2ab =>2ab = 29 - 9 =>2ab = 20. Therefore, ab=10. …
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Web30 mrt. 2024 · (iii) a2 + 2ab + b2 a2 + 2ab + b2 Putting a = 3, b = 2 = (3)3 − (2)3 = (3) − 2 (3) (2) + (2)2 = 21 + 4 = 25 Example 9 Find the value of the following expressions for a … WebIf a+b+c =9 and a² + b²+ c²=35 find the value of a³ + b³ + c³ - 3ab Solution (a+b+c)²=9²=81 a²+b²+c²+2ab+2bc+2ca=81 a²+b²+c²+2ab+2bc+2ca- (a²+b²+c²)=81-35 2ab+2bc+2ca=46 2 (ab+bc+ca)=46 (ab+bc+ca)=23 a³+b³+c³-3abc= (a+b+c) (a²+b²+c²-ab-bc-ca) =9 (35- (ab+bc+ca)) =9 (35-23) =9 (12)=108 Suggest Corrections 26 Similar questions Q. new macbook pro gaming performance
If a-b=4 and a^3-b^3=88 then find the value of a^2-b^2=?
Web13 feb. 2024 · Thus if ( A − B) ( A + B) = A 2 − B 2 then A B − B A = O, the zero matrix. Equivalently, A B = B A. Note that matrix multiplication is not commutative, namely, A B ≠ B A in general. Thus we can disprove the statement if we find matrices A and B such that A B ≠ B A. For example, let A = [ 1 1 0 0] and B = [ 0 1 0 1]. Then we have WebIf a + b = 9 and ab = 10, find the value of a 2+b 2. Medium Solution Verified by Toppr Given, a + b = 9 and ab = 10 Now, squaring a + b = 9 on both sides, we have (a+b) 2=(9) a 2+b 2+2ab=81 a 2+b 2+2×10=81 a 2+b 2+20=81 a 2+b 2=81−20=61 ∴ a 2+b 2=61 Was this answer helpful? 0 0 Similar questions If a + b = 5 and ab = 6, find a 2+b 2. Easy Web9 apr. 2024 · ⇒ a 3 + b 3 = 35 Therefore the value of a 3 + b 3 is 35. Note: So you might be thinking why we use this formula (1), because in the question the given values are (a + … intrahepatic choledochal cyst